THE WORLD'S LARGEST WEB DEVELOPER SITE
HTMLCSSJAVASCRIPTSQLPHPBOOTSTRAPJQUERYANGULARXML
 

XML DOM Parser Errors


XML Parser Error

When trying to open an XML document, a parser-error may occur.

If the parser encounters an error, it may load an XML document containing the error description.

The code example below tries to load an XML document that is not well-formed.

You can read more about well-formed XML in XML Syntax.

Example

<html>
<body>

<p id="demo"></p>

<script>
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
  if (xhttp.readyState == 4 && xhttp.status == 200) {
    myFunction(xhttp);
  }
};
xhttp.open("GET", "note_error.xml", true);
xhttp.send();

function myFunction(xml) {
  var parser, xmlDoc;
  parser = new DOMParser();
  xmlDoc = parser.parseFromString(xml.responseText,"text/xml");
  document.getElementById("demo").innerHTML =
  myLoop(xmlDoc.documentElement);
}

function myLoop(x) {
  var i, y, xLen, txt;
  txt = "";
  x = x.childNodes;
  xLen = x.length;
  for (i = 0; i < xLen ;i++) {
    y = x[i];
    if (y.nodeType != 3) {
      if (y.childNodes[0] != undefined) {
        txt += myLoop(y);
      }
    } else {
    txt += y.nodeValue + "<br>";
    }
  }
  return txt;
}
</script>

</body>
</html>
Try it Yourself »

Look at the XML file: note_error.xml